## Another Algebra word problem :(?

### Another Algebra word problem :(?

I can do normal problems well, but the word problems always get me. Here it is

Adam earns \$37 mowing lawns. At his favorite store it costs \$6.50 to rent a newly-released videogame and \$4 to rent movies.

A. write an equation that gives the amount of money Adam has left, b, after renting 1 video game and m, movies.

B.How many movies can he rent if he rents no video games?

C. How many videogames can he rent if he rents no movies?

If you can show a bit on how you got the answers and not just give them to me that would be helpful. I am horrid at word problems, thanks guys. filippo

Posts: 55
Joined: March 12th, 2012, 4:58 pm

### Another Algebra word problem :(?

Rental cost is given by 6.5v + 4m.....so, money left would be:

b = 37 - 6.5v - 4m...........so, when v = 1 we have:

b = 37 - 6.5 - 4m

b = 30.5 - 4m.........(A)

When v = 0 we have:

b = 37 - 4m

so, m = 37/4 = 9.25......i.e. maximum 9 movies.......(B)

When m = 0 we have:

b = 37 - 6.5v

so, v = 37/6.5.......i.e. maximum 5 videogames.......(C)

:)> blanco

Posts: 52
Joined: March 4th, 2012, 9:43 pm

### Another Algebra word problem :(?

A. The money he spends is 6.5+4m. The money he has left is b=37-(6.5+4m)
B. 37/4=9.25 so he can rent 9 movies.
C. 37/6.5=5.69 so he can rent 5 games beechy4

Posts: 38
Joined: June 21st, 2012, 6:15 pm

### Another Algebra word problem :(?

A. i dont really get it
B. 37 / 4 = 9.25. but he cant rent 9.25 movies so answer is 9
C.37 / 6.5 = 5.69 nut he cant rent 5.69 video games so the answer is 5 harlowe

Posts: 37
Joined: June 20th, 2012, 10:05 pm

### Another Algebra word problem :(?

A. i dont really get it
B. 37 / 4 = 9.25. but he cant rent 9.25 movies so answer is 9
C.37 / 6.5 = 5.69 nut he cant rent 5.69 video games so the answer is 5
A b = 37 - 6.50 - 4m

B 9 movies ( 9 X 4 = 36 \$ )

C 5 video games ( 5 X 6.5 = 32.50 \$ ) galtero

Posts: 91
Joined: October 29th, 2011, 4:57 pm